[SciPy-User] convolve/deconvolve
jkhilmer@chemistry.montan...
jkhilmer@chemistry.montan...
Fri Feb 1 10:02:59 CST 2013
I have some old code for Richardson-Lucy deconvolution, although the method
is so simple there's no reason not to try it yourself.
Jonathan
On Fri, Feb 1, 2013 at 7:50 AM, <josef.pktd@gmail.com> wrote:
> On Fri, Feb 1, 2013 at 9:50 AM, <josef.pktd@gmail.com> wrote:
> > On Fri, Feb 1, 2013 at 9:23 AM, François Boulogne <fboulogne@sciunto.org>
> wrote:
> >> Hi,
> >>
> >> I need to deconvolve a signal with a filter. I had a look in the
> >> documentation. The function exists but the docstring is missing and I'm
> >> not satisfied of the result I got from a "simple" example.
> >>
> >> filter = np.array([0,1,1,1,1,0])
> >> step = np.array([0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
> >> 1, 1, 1, 1])
> >> # I convolve both
> >> res = convolve(step, filter, 'valid')
> >> # and it returns a slope as expected
> >> array([0, 0, 1, 2, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4])
> >>
> >> Now, I want to deconvolve.
> >> deconvolve(res, filter)
> >> # oops, it raises an exception
> >> ValueError: BUG: filter coefficient a[0] == 0 not supported yet
> >>
> >> # well, let's try this
> >> deconvolve(res, filter+1e-9)
> >> (array([ 0.00000000e+00, 0.00000000e+00, 1.00000000e+09,
> >> -9.99999999e+17, 9.99999999e+26, -9.99999999e+35,
> >> 9.99999999e+44, -9.99999999e+53, 9.99999999e+62,
> >> -9.99999999e+71, 9.99999999e+80, -9.99999999e+89]),
> >> array([ 0.00000000e+00, 0.00000000e+00, 1.11022302e-16,
> >> -8.27130862e-08, -4.42500000e+01, 5.46901335e+10,
> >> 8.27266814e+19, 7.56858250e+28, -8.74285726e+37,
> >> 9.99419626e+46, 8.27205507e+55, -8.26933326e+64,
> >> 9.99999999e+89, 9.99999999e+89, 9.99999999e+89,
> >> 1.00000000e+90, 9.99999999e+80]))
> >>
> >> It's better but I do not recognize my signal :)
> >> 1/ Am I misunderstanding or missing something?
> >> 2/ How can I do it correctly?
> >
> > AFAICS:
> >
> > not supported, maybe using the numpy polynomial might work for the
> deconvolution
> >
> > from the docstring of lfilter, which is used by deconvolve:
> >
> > a : array_like
> > The denominator coefficient vector in a 1-D sequence. If
> ``a[0]``
> > is not 1, then both `a` and `b` are normalized by ``a[0]``.
> >
> > with the normalization your 1e-9 blows up the calculations.
> >
> > (it's been a long time since I tried to figure out deconvolve, and I
> > always had 1 in the first position)
> >
> > Josef
> >
> >
> >>
> >> I also noted that no test exists for deconvolve() :(
>
> Volunteers ?
>
> Josef
>
>
> >>
> >> Cheers,
> >> François.
> >> _______________________________________________
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> >> SciPy-User@scipy.org
> >> http://mail.scipy.org/mailman/listinfo/scipy-user
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