[SciPy-User] a=b operation in numpy

Frédéric Parrenin parrenin.ujf@gmail....
Tue Jul 2 10:24:59 CDT 2013


Dear all,

Does anybody know what is the rational in defining for the 'a=b' operation
a pointer copy and not a complete copy?
It is inconsistent from an algebraic point of view, since 'a=b' is not the
same as 'a=b+0'.
And it is also confusing for starters.

Best regards,

Frédéric Parrenin
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