[IPython-dev] interrupting local kernels
Fri Feb 24 12:58:51 CST 2012
The nanny process is ultimately the way we need to go, otherwise you won't
ever be able to interrupt remote kernels.
On Thu, Feb 23, 2012 at 23:04, Matt Terry <email@example.com> wrote:
> I want to be able to interrupt an ipython kernel that is local to my
> machine, but not owned by the current process. I recognize that the
> general problem of interrupting a truly remote kernel is a harder
> problem and i'm not explicitly not addressing that. However, I think
> interrupting a local kernel is worth having a special case.
> All you need to interrupt a local kernel is its pid, so you can send a
> SIGINT to the appropriate process. The only way I can think of to get
> that information is to ask the remote kernel (over the shell channel)
> to return the output of "os.getpid()". The kernel might restart and
> change pid, so you'd have to poll. This seems ugly and failure prone.
> What you need is
> A) the kernel to have a nanny that always knows what the kernel's pid is
> B) the kernel to communicate its pid someway other than over the shell
> What about using the heartbeat channel to echo the pid? To my
> understanding, the heart beats even if the kernel is chugging away.
> We could have the heartbeat channel return the pid instead of the
> uuid, or we could return them both. Alternatively, we could pid
> information in a file in .ipython/somewhere, but that seems
> potentially contentious.
> IPython-dev mailing list
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