[Numpy-discussion] Offset 2D arrays
Herbert L. Roitblat
roitblat at hawaii.edu
Tue Sep 18 10:57:03 CDT 2001
This will work:
b=zeros ((3,3))
b[:2,:2] = b[:2,:2] + a[1:,1:]
You need to know the size of a to use this scheme.
----- Original Message -----
From: "Chris Barker" <chrishbarker at home.net>
To: "Mike Romberg" <romberg at fsl.noaa.gov>
Cc: <numpy-discussion at lists.sourceforge.net>
Sent: Monday, September 17, 2001 2:03 PM
Subject: Re: [Numpy-discussion] Offset 2D arrays
> Mike Romberg wrote:
> >
> > I am attempting to create 2D arrays which are offset copies of a
> > given starting array. For example if I have a 2D array like this:
>
> > have any ideas?
>
> This is not quite as clean as i would like, but this will work:
>
> >>> a = array([[1, 2, 3],
> ... [4, 5, 6],
> ... [7, 8, 9]])
> >>> m,n = a.shape
> >>> b[:m-1,:n-1] = a[1:,1:]
> >>> b
> array([[5, 6, 0],
> [8, 9, 0],
> [0, 0, 0]])
> >>>
>
> if b does not have to be the same shape as a, then it is really easy:
>
> >>> b = a[1:,1:]
>
> -Chris
>
>
> --
> Christopher Barker,
> Ph.D.
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