[Numpy-discussion] erfc

Karthikesh Raju karthik at james.hut.fi
Wed Jun 2 09:38:08 CDT 2004

Hi All,

Thankx to everyone for my previous "Random Numbers" question. Ok, do
we have the complementary error function in numarray?

i mean erfc(z) = 1 - erf(z)
               = \frac{2}{\pi} \int_z^\infy e^{t^2}dt

(just used LaTeX notation, ran out of ideas to represent it otherwise)

Warm regards


Karthikesh Raju,		    email: karthik at james.hut.fi
Researcher,			    http://www.cis.hut.fi/karthik
Helsinki University of Technology,  Tel: +358-9-451 5389
Laboratory of Comp. & Info. Sc.,    Fax: +358-9-451 3277
Department of Computer Sc.,
P.O Box 5400, FIN 02015 HUT,

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