[Numpy-discussion] Accessing rank-0 array value?
Nadav Horesh
nadavh at visionsense.com
Mon Jun 7 02:51:07 CDT 2004
b has a scalar properties:
>>> b+3
5
>>> b.rank
0
The odd issue is that rank>0 arrays keeps their type in similar operations:
>>> a = array((2,), type=Int16)
>>> a
array([2], type=Int16)
>>> a + 3
array([5], type=Int16)
I would expect that rank 0 arrays would behave like scalars with a given numarray type (Int8, UInt64, ...).
Nadav.
-----Original Message-----
From: Peter Verveer [mailto:verveer at embl-heidelberg.de]
Sent: Mon 07-Jun-04 12:27
To: Francesc Alted
Cc: Numpy Discussion List
Subject: Re: [Numpy-discussion] Accessing rank-0 array value?
For instance:
>>> float(b)
2.0
or probably more appropriate since it retains the type:
>>> b[()]
2
Both not very intuitive, are there any better ways?
On 7 Jun 2004, at 11:17, Francesc Alted wrote:
> Hi,
>
> Perhaps this is a stupid question, but I did not found any easy way to
> get
> the python object value from a rank-0 numarray array. That is:
>
>>>> from numarray import *
>>>> b=array(2)
>>>> b
> array(2)
>>>> b[0]
> Traceback (most recent call last):
> File "<stdin>", line 1, in ?
> IndexError: Too many indices
>
> In C, that seem to be possible provided you use the call:
> PyObject* PyArray_Return(PyArrayObject *apr)
>
> Is there any way to do that in python?
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