# [Numpy-discussion] Counting array elements

Todd Miller jmiller at stsci.edu
Thu Oct 21 15:04:04 CDT 2004

```On Thu, 2004-10-21 at 14:30, Todd Miller wrote:
> On Thu, 2004-10-21 at 13:55, Stephen Walton wrote:
> > Is there some simple way of counting the number of array elements which
> > satisfy a certain condition?  It is easy to do
> >
> > A[A<=1].sum()
> >
> > to sum all the values of A which are less than 1, but there doesn't seem
> > to be a count() method.  I tried
> >
> > (A<=1).sum()
> >
> > but this throws an exception at numarray 1.1.  If I try
>
> This works now in CVS and will be part of numarray-1.2.

Stephen tried this and it turns out my earlier statement was untrue,
(A<=1).sum() doesn't do anything reasonable, even in CVS.  The problem
is that sum() is written (without direct C support) to conserve
storage.  As a result,  it doesn't do implicit
> Another more
> tedious approach which works for numarray-1.1 is:
>
> (A <= 1).astype('Int32').sum()
>

There's also a prettier approach that works for 1.1 that I forgot about:

(A <= 1).sum('Int32')

> > sum(A<=value)
> >
> > I have to nest multiple sums if A has rank greater than 1, plus the sum
> > overflows if A is large, apparently because boolean gets treated as
> > Int8.  (Try A=arange(1024,shape=(32,32));sum(sum(A<=1024)).  You get
> > zero.)  The following works:
> >
> > array(A<=1024,type=Int32).sum()
> >
> > but is awkward.  Am I missing an obvious better alternative?  If not,
> > I'm going to file an RFE :-) .
>
> I don't think there's any need for an RFE, provided you're satisfied
> with (A<=1).sum().
>
> Regards,
> Todd
>
>
>
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