[Numpy-discussion] trivial question: how to compare dtype - but ignoring byteorder ?

Travis Oliphant oliphant.travis at ieee.org
Mon Jul 24 14:36:56 CDT 2006

Sebastian Haase wrote:
> Hi,
> if I have a numpy array 'a'
> and say:
> a.dtype == numpy.float32
> Is the result independent of a's byteorder ?
> (That's what I would expect ! Just checking !)

I think I misread the question and saw "==" as "="

But, the answer I gave should still help:  the byteorder is a property 
of the data-type.  There is no such thing as "a's" byteorder.   Thus, 
numpy.float32 (which is actually an array-scalar and not a true 
data-type) is interepreted  as a machine-byte-order IEEE floating-point 
data-type with 32 bits.   Thus, the result will depend on whether or not 
a.dtype is machine-order or not.


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