can this be made faster?
Daniel Mahler
dmahler at gmail.com
Mon Oct 9 00:23:18 CDT 2006
On 10/8/06, Greg Willden <gregwillden at gmail.com> wrote:
> On 10/8/06, Daniel Mahler <dmahler at gmail.com> wrote:
> >
> > >>> a
> > array([0, 0])
> > >>> b
> > array([0, 1, 0, 1, 0])
> > >>> c
> > array([1, 1, 1, 1, 1])
> >
>
>
> Well for this particular example you could do
> a=array([len(b)-sum(b), sum(b)])
> Since you are just counting the ones and zeros.
>
> This next one is a little closer for the case when c is not just a bunch of
> 1's but you still have to know how the highest number in b.
> a=array([sum(c[b==0]), sum(c[b==1]), ... sum(c[b==N]) ] )
>
> So it sort of depends on your ultimate goal.
> Greg
> Linux. Because rebooting is for adding hardware.
In my case all a, b, c are large with b and c being orders of
magnitude lareger than a.
b is known to contain only, but potentially any, a-indexes, reapeated
many times.
c contains arbitray floats.
essentially it is to compute class totals
as in total[class[i]] += value[i]
Daniel
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