Should numpy.sqrt(-1) return 1j rather than nan?

Sven Schreiber svetosch at
Wed Oct 11 15:46:59 CDT 2006

Travis Oliphant schrieb:

>> If not, shouldn't
>> numpy.sqrt(-1) raise a ValueError instead of returning silently nan?
> This is user adjustable.  You change the error mode to raise on 
> 'invalid' instead of pass silently which is now the default.
> -Travis

Could you please explain how this adjustment is done, or point to the
relevant documentation.
Thank you,

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