Should numpy.sqrt(-1) return 1j rather than nan?

David Goldsmith David.L.Goldsmith at
Thu Oct 12 01:27:19 CDT 2006

Travis Oliphant wrote:
> What could be simpler? ;-)
Having sqrt(-1) return 1j (without having to remember that in order to 
get this, you have to write sqrt(-1+0j) instead).


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