Should numpy.sqrt(-1) return 1j rather than nan?
Travis Oliphant
oliphant.travis at ieee.org
Thu Oct 12 02:41:46 CDT 2006
David Goldsmith wrote:
>>
>>
> I don't use scipy (and don't want to because of the overhead) but it
> sounds like I should because if I'm taking the square root of a variable
> whose value at run time happens to be real but less than zero, I *want*
> the language I'm using to return an imaginary; in other words, it's not
> the scipy behavior which "scares" me, its the numpy (which I do/have
> been using) behavior.
O.K. Well the functions you want are in numpy.lib.scimath. I should
have directed you there. You actually don't need scipy installed at
all. Just import sqrt from numpy.lib.scimath. I'm sorry I
misunderstood the issue.
-Travis
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