Should numpy.sqrt(-1) return 1j rather than nan?
Mark Bakker
markbak at gmail.com
Thu Oct 12 02:58:46 CDT 2006
My vote is for consistency in numpy.
But it is unclear what consistency is.
What is truly confusing for newbie Python users (and a source for error even
after 5 years of Python programming) is that
>>> 2/3
0
In that respect, I would think
>>> numpy.sqrt(2)
should give 1, but it gives 1.4142135623730951
So numpy does typechecking anyway (it gets an integer and makes it a float).
If that is the consistent behavior, then by all means
>>> sqrt(-1)
should return 1j.
Wouldn't that be the consistent thing to do????
Mark
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