Should numpy.sqrt(-1) return 1j rather than nan?
David Goldsmith
David.L.Goldsmith at noaa.gov
Thu Oct 12 02:18:57 CDT 2006
Travis Oliphant wrote:
> David Goldsmith wrote:
>
>> Travis Oliphant wrote:
>>
>>
>>> What could be simpler? ;-)
>>>
>>>
>> Having sqrt(-1) return 1j (without having to remember that in order to
>> get this, you have to write sqrt(-1+0j) instead).
>>
>>
>>
> That's exactly what scipy.sqrt(-1) does. That was my point.
>
But I don't want to have to use scipy (which so far I haven't needed for
any other reason) just to get this one behavior. But my personal
preferences aside, I say again: if numpy doesn't behave this way, you
*will* be "scaring" away many potential users. If you can live with
that, so be it.
DG
DG
> -Travis
>
>
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