[Numpy-discussion] take(..., out=something) does not seem to work
Jouni K. Seppänen
jks@iki...
Fri Apr 27 15:16:28 CDT 2007
Hi,
Either I have completely misunderstood what the out= arg to the take
function is supposed to do, or there is a bug in numpy 1.0.2, as
demonstrated below.
First, some initialization:
In [1]: from numpy import *
In [2]: a=arange(12).reshape((3,4))
In [3]: a
Out[3]:
array([[ 0, 1, 2, 3],
[ 4, 5, 6, 7],
[ 8, 9, 10, 11]])
Let's try take without an output argument:
In [4]: take(a, [0,2], axis=1)
Out[4]:
array([[ 0, 2],
[ 4, 6],
[ 8, 10]])
Good. Now let's create an array of the right size and dtype, and use
it for output:
In [5]: b = zeros_like(_)
In [6]: take(a, [0,2], axis=1, out=b)
Out[6]:
array([[ 0, 2],
[ 4, 6],
[ 8, 10]])
In [7]: b
Out[7]:
array([[0, 0],
[0, 0],
[0, 0]])
It seems that b was not affected at all.
--
Jouni K. Seppänen
http://www.iki.fi/jks
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