[Numpy-discussion] matrix multiplication A x, x has some zeros

Alan G Isaac aisaac@american....
Fri Dec 14 17:53:46 CST 2007

>> idx=N.ravel(x)!=0
>> A[:,idx]*x[idx] 

On Fri, 14 Dec 2007, dmitrey apparently wrote:
> I expect <A,x> being vector of length n A and x change 
> every iter. A is not sparse. 

Still, whenever x has a lot of zeros,
this should have a substantial payoff.
That seems the only exploitable information
you have offered in the problem.


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