[Numpy-discussion] non-intuitive behaviour in numpy.array([list], numpy.object_)
Garnet Chan
gkc1000@gmail....
Thu Jan 3 14:58:25 CST 2008
Thanks - that's clear I guess, although I still think that it might be
less confusing if numpy did not try to be clever!
On 1/3/08, Christopher Barker <Chris.Barker@noaa.gov> wrote:
> Garnet Chan wrote:
> > When constructing an numpy object array from a list of numpy arrays,
> > one observes the following behaviour
> >
> >>>> import numpy as N
> >>>> a=[N.zeros([2,2], N.object_), N.zeros([2,2], N.object_)]
> >>>> b=N.array(a, N.object_)
> >>>> print b.shape
> > (2, 2, 2)
> >>>> a=[N.zeros([2,2], N.object_), N.zeros([2,1], N.object_)]
> >>>> b=N.array(a, N.object_)
> >>>> print b.shape
> > (2,)
> >
> > I understand that this is because in the 1st instance, numpy is trying
> > to be clever and recognises that the list of arrays "a" can be
> > reshaped into a 3-d array. But surely, if we are constructing an array
> > with the object_ dtype, the first should also be converted into a
> > shape (2,) array?
>
> arrays of the _object dtype are plain weird -- as arbitrary objects can
> be sequences (and mutable ones at that!), it's impossible to
> automatically create the shape of arrays of objects that the user wants.
> Perhaps it could be a bit smarter to be more consistent, but what you
> really need to do is define the shape for numpy, and not expect it to
> figure out what you want -- even if it does the right thing with one
> example.
>
> If you want a (2,) array, then do this:
>
> >>> b = N.empty(2, dtype=N.object)
> >>> b[:]=a
> >>> b.shape
> (2,)
>
> -Chris
>
>
> --
> Christopher Barker, Ph.D.
> Oceanographer
>
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