[Numpy-discussion] array_equal returns True and 0
Keith Goodman
kwgoodman@gmail....
Mon Jul 7 11:47:58 CDT 2008
On Mon, Jul 7, 2008 at 9:40 AM, Keith Goodman <kwgoodman@gmail.com> wrote:
> On Mon, Jul 7, 2008 at 9:30 AM, Keith Goodman <kwgoodman@gmail.com> wrote:
>> I'm writing the doc string for array_equal. From the existing one-line
>> doc string I expect array_equal to return True or False. But I get
>> this:
>>
>>>> np.array_equal([1,2], [1,2])
>> True
>>>> np.array_equal([1,2], [1,2,3])
>> 0
>>>> np.array_equal(np.array([1,2]), np.array([1,2,3]))
>> 0
>>>> np.__version__
>> '1.1.0'
>
> Oh, it's written in python:
>
> def array_equal(a1, a2):
> """Returns True if a1 and a2 have identical shapes
> and all elements equal and False otherwise.
> """
> try:
> a1, a2 = asarray(a1), asarray(a2)
> except:
> return 0
> if a1.shape != a2.shape:
> return 0
> return logical_and.reduce(equal(a1,a2).ravel())
>
> Could someone change the 0's to False? Otherwise it will return True,
> False or 0.
>
>>> np.array_equal([3,2], [1,2])
> False
Sorry for all the messages.
array_equiv also returns 0.
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