[Numpy-discussion] Eigenvectors in Matlab vs. Numpy
Sun Jun 29 21:34:33 CDT 2008
On Sun, Jun 29, 2008 at 21:00, Saket <firstname.lastname@example.org> wrote:
> Hmm... so the relationship Ax = Lx should hold for every eigenvalue
> and corresponding eigenvector of A, right? But, consider the first
> eigenvalue,eigenvector pair:
> for i,eval in enumerate(d):
> print abs(numpy.dot(A,v[i]) - numpy.dot(eval,v[i])).max()
> Outputs: 1.928
> I thought maybe the ith eigenvector corresponds to a different (not
> the ith) eigenvalue, but there doesn't seem to be any eigenvalue which
> corresponds to the ith eigenvector such that the relationship holds...
The eigenvectors are the columns, not the rows.
"I have come to believe that the whole world is an enigma, a harmless
enigma that is made terrible by our own mad attempt to interpret it as
though it had an underlying truth."
-- Umberto Eco
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