[Numpy-discussion] Create a numpy array from an array of a C structure

Robert Kern robert.kern@gmail....
Sun Mar 9 04:15:19 CDT 2008

On Sun, Mar 9, 2008 at 2:57 AM, mani sabri <mani.sabri@gmail.com> wrote:
> Hello
>  Is it possible to create a numpy array from an array of a C structure like
>  this?
>  struct RateInfo
>   {
>    unsigned int      ctm;
>    double            open;
>    double            low;
>    double            high;
>    double            close;
>    double            vol;
>   };

Sure. On the numpy side, you would make an record array with the
appropriate dtype and size.

In [1]: from numpy import *

In [2]: dt = dtype([('ctm', uint), ('open', double), ('low', double),
('high', double), ('close', double), ('vol', double)])

In [3]: a = empty(10, dtype=dt)

On the C side, you would iterate through your C array and your numpy
array and just assign elements from the one to the other. If you have
a contiguous C array, you could also just use memcpy().

This is probably reliable because all of your struct members take up
multiples of 4 bytes and most C compilers will pack those without any
space between them. If you were mixing, say, chars and doubles, the C
compiler may try to align the doubles on a 4-byte boundary (or
possibly another boundary, but 4-bytes is common). In that case, you
will have to figure out how your C compiler is packing the member and
emulate that in your dtype. Each of the tuples in the constructor can
have a third element which represents the byte offset of that member
from the beginning of the struct.

In [4]: dt2 = dtype([('ctm', uint, 0), ('open', double, 4), ('low',
double, 12), ('high', double, 20), ('close', double, 28), ('vol',
double, 36)])

Robert Kern

"I have come to believe that the whole world is an enigma, a harmless
enigma that is made terrible by our own mad attempt to interpret it as
though it had an underlying truth."
  -- Umberto Eco

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