[Numpy-discussion] indexing problem
Tue Aug 18 11:27:21 CDT 2009
2009/8/18 Ernest Adrogué <firstname.lastname@example.org>:
> 18/08/09 @ 07:33 (-0700), thus spake Robert Kern:
>> 2009/8/18 Ernest Adrogué <email@example.com>:
>> > Hi,
>> > Suppose I have a 3-dimansional array, where one dimension
>> > is time. I'm not particularly interested in selecting specific
>> > moments in time, so most of the time I won't be indexing this
>> > dimension.
>> > Intuitively, one would make time the third dimension, but if
>> > you do that you have to specifiy the time in every index, which
>> > is annoying, because then all indices must start with an empty
>> > slice, e.g.,
>> > a[:,1]
>> > a[:,:,3]
>> > a[:,0,1]
>> > etc. On the other hand, the arrays resulting from indexing have
>> > all elements sorted by time, which is a good thing.
>> > Then, if I change it and make time the first dimension, it's
>> > handy because I can omit time in indices, BUT then the sub-arrays
>> > produced by indexing are not sorted by time!
>> I do not know what you mean by "not sorted by time". You can keep the
>> sub-arrays sorted however you like regardless of the index used for
>> time. Can you show us an example of the problem you are seeing?
> Sorry for not explaining myself clearly enough.
> I'm using a masked arrays, and I call the compressed() method on
> the sub-arrays resulting from indexing, which gives a 1-d array. Is
> this 1-d array that isn't sorted the way I'd like.
> I'll try to explain this with an example. Here is a 3-d array
> that represents a 2-d array in differents moments in time (for
> ilustration purposes all elements in the 2-d array increase by
> one at each time point:
> In : x=np.zeros((3,2,2))
> In : x=1
> In : x=2
> In : x=3
> In : x
> array([[[ 1., 1.],
> [ 1., 1.]],
> [[ 2., 2.],
> [ 2., 2.]],
> [[ 3., 3.],
> [ 3., 3.]]])
> Then if I take the elements [:,0] and flatten the resulting
> array, we can see that the resulting array has its elements sorted
> by time:
> In : x[:,0].flatten()
> Out: array([ 1., 1., 2., 2., 3., 3.])
> But then I thought that it would be nice to arrange the data
> differently, so that the dimension that represents time can be
> omitted in the index.
> Therefore, I re-arrange the data in this way:
> In : x=np.zeros((2,2,3))
> In : x[:,:,0]=1
> In : x[:,:,1]=2
> In : x[:,:,2]=3
> In : x
> array([[[ 1., 2., 3.],
> [ 1., 2., 3.]],
> [[ 1., 2., 3.],
> [ 1., 2., 3.]]])
> But then, the flattened arrays I get are no longer in
> time-ascending order:
> In : x.flatten()
> Out: array([ 1., 2., 3., 1., 2., 3.])
> It's a bit difficult to explain, but I hope it's more clear now!
"I have come to believe that the whole world is an enigma, a harmless
enigma that is made terrible by our own mad attempt to interpret it as
though it had an underlying truth."
-- Umberto Eco
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