[Numpy-discussion] extract elements of an array that are contained in another array?
Fri Jun 5 00:56:14 CDT 2009
On Fri, Jun 5, 2009 at 1:48 AM, Robert Cimrman <firstname.lastname@example.org> wrote:
> email@example.com wrote:
>> On Thu, Jun 4, 2009 at 4:30 PM, Gael Varoquaux
>> <firstname.lastname@example.org> wrote:
>>> On Thu, Jun 04, 2009 at 10:27:11PM +0200, Kim Hansen wrote:
>>>> "in(b)" or "in_iterable(b)" method, such that you could do a.in(b)
>>>> which would return a boolean array of the same shape as a with
>>>> elements true if the equivalent a members were members in the iterable
>>> That would really by what I would be looking for.
>> Just using "in" might promise more than it does, eg. it works only for
>> one dimensional arrays, maybe "in1d". With "in", I would expect a
>> generic function as in python that works with many array types and
>> dimensions. (But I haven't checked whether it would work with a 1d
>> structured array or object array.)
>> I found arraysetops because of unique1d, but I didn't figure out what
>> the subpackage really does, because I was reading "arrayse-tops"
>> instead of array-set-ops"
> I am bad in choosing names, but note that numpy sub-modules usually do
> not use underscores, so array_set_ops would not fit well.
I would have chosen something like setfun. Since this is in numpy
that sets refers to arrays should be implied.
>> BTW, for the docs, I haven't found a counter example where
>> np.setdiff1d gives the wrong answer for non-unique arrays.
> In : np.setmember1d( [1, 1, 2, 4, 2], [3, 2, 4] )
> Out: array([ True, False, True, True, True], dtype=bool)
setdiff1d diff not member
Looking at the source, I think setdiff always works even if for
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