[Numpy-discussion] vectorization of vectorization
Thu Aug 19 17:36:08 CDT 2010
With slight modification I got it work (fucnt as before):
funct(orders, num.arange(1e6)[:, num.newaxis], powers).prod(axis = 1)
This gives me exactly what I need! Thanks a lot.
ps: I don't know how to post my thank you on the discussion list.
Date: Thu, 19 Aug 2010 14:32:42 -0700
Subject: Re: [Numpy-discussion] vectorization of vectorization
This seems simple, so perhaps I am missing something, but what about this:
special.iv(orders[:, newaxis], arange(1e6)[newaxis, : ], powers[:, newaxis]).prod(axis = 2)
This will probably use up a bit slow/memoryintensive, so you probably want to use numexpr to speed it up a bit.
On Thu, Aug 19, 2010 at 2:22 PM, sm lkd <firstname.lastname@example.org> wrote:
Here's my problem: for each value t of an array (from 0 to 1e6) a smaller array is computed (size between 2-6). To compute the smaller array, I have a function (which can be easily vectorized if necessary) which takes t and an array of powers of t. The return is an array of modified Bessel function values, i.e.:
def funct(order, t, power):
return special.iv(order, t)**power
Note that order and power are arrays after this vectorization:
vec_func = sp.vectorization(func)
Right this is how it's used:
for i in range(1000000):
y[i] = vec_func(orders, t, powers).prod()
Of course, it is desirable to vectorize it it terms of t. I have tried different methods but still cannot make it work. Any suggestions or ointers?
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