# [Numpy-discussion] How construct custom slice

Mario Moura moura.mario@gmail....
Mon Dec 27 12:58:38 CST 2010

```Hi Mr. Goodman

Thanks a lot. Works Fine

Reagards

Mario Moura

2010/12/27 Keith Goodman <kwgoodman@gmail.com>:
> On Mon, Dec 27, 2010 at 10:36 AM, Mario Moura <moura.mario@gmail.com> wrote:
>> Hi Folks
>>
>> a = np.zeros((4,3,5,55,5),dtype='|S8')
>> myLen = 4 # here I use myLen = len(something)
>> li = [3,2,4] # li from a list.append(something)
>> sl = slice(0,myLen)
>> tmpIndex = tuple(li) + sl + 4  # <== Here my problem
>> a[tmpIndex]
>>
>> # So What I want is:
>> fillMe = np.array(['foo','bar','hello','world'])
>> # But I cant contruct by hand like this
>> a[3,2,4,:4,4] = fillMe
>> a
>>
>> Again. I need construct custom slice from here
>> tmpIndex = tuple(li) + sl + 4
>> a[tmpIndex]
>
> First let's do it by hand:
>
>>> a = np.zeros((4,3,5,55,5),dtype='|S8')
>>> fillMe = np.array(['foo','bar','hello','world'])
>>> a[3,2,4,:4,4] = fillMe
>
> Now let's try using an index:
>
>>> b = np.zeros((4,3,5,55,5),dtype='|S8')
>>> myLen = 4
>>> li = [3,2,4]
>>> sl = slice(0,myLen)
>
> Make index:
>
>>> idx = range(a.ndim)
>>> idx[:3] = li
>>> idx[3] = sl
>>> idx[4] = 4
>>> idx = tuple(idx)
>
> Compare results:
>
>>> b[idx] = fillMe
>>> (a == b).all()
>   True
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```