[Numpy-discussion] determinant of a scalar not handled
Skipper Seabold
jsseabold@gmail....
Mon Jul 26 11:45:22 CDT 2010
Right now np.linalg.det does not handle scalars or 1d (scalar) arrays.
It first tests that an array is 2d, then if it is square. This seems
redundant to me.
This currently works
In [20]: np.linalg.det([[1]])
Out[20]: 1.0
but
In [21]: np.linalg.det([1])
<snip>
LinAlgError: 1-dimensional array given. Array must be
two-dimensional
The diff attached to this ticket
<http://projects.scipy.org/numpy/ticket/1556> gives
In [3]: np.linalg.det([[1]])
Out[3]: 1.0
In [4]: np.linalg.det([1])
Out[4]: 1.0
In [5]: np.linalg.det(1)
Out[5]: 1.0
Skipper
More information about the NumPy-Discussion
mailing list