[Numpy-discussion] np.choose() question
Andreas
lists@hilboll...
Tue Jun 8 14:52:29 CDT 2010
Hi,
actually, I meant to reply to Mark's mail, as I used his solution ;)
Thanks!
On 06/08/2010 09:21 PM, Gökhan Sever wrote:
> If we were at so or ask.scipy I would vote for Mark's solution :)
>
> Usually in cases like yours, I tend to use the shortest version of the
> solutions.
>
> On Tue, Jun 8, 2010 at 2:08 PM, Andreas Hilboll <lists@hilboll.de
> <mailto:lists@hilboll.de>> wrote:
>
> Hi,
>
> > newtimes = [times[idx[x][y]] for x in range(2) for y in range(2)]
> > np.array(newtimes).reshape(2,2)
> > array([[104, 102],
> > [103, 101]])
>
> Great, thanks a lot!
>
> Cheers,
>
> Andreas.
>
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>
> --
> Gökhan
>
>
>
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