# [Numpy-discussion] Simple problem. Is it possible without a loop?

Robert Elsner mlist@re-factory...
Wed Jun 9 03:31:07 CDT 2010

```> Given a certain value delta, I would like to get a subset of x, named
> y,
> where (y[i+1] - y[i]) >= delta

So in fact the problem is to find y such that

(y[i(k)+n] - y[i(k)]) >= delta
for n <= len(x) - 1 - i
and i(0) = 0, i(k+1) = i(k) + n

? Well a loop or list comparison seems like a good choice to me. It is
much more obvious at the expense of two LOCs. Did you profile the two
possibilities and are they actually performance-critical?

cheers

Am Mittwoch, den 09.06.2010, 10:14 +0200 schrieb "V. Armando Solé":
> That was my first thought, but that only warrants me to skip one point
> in x but not more than one.
>
>  >>> x= numpy.arange(10.)
>  >>> delta = 3
>  >>> print x[(x[1:] - x[:-1]) >= delta]
> []
>
> instead of the requested [0, 4, 8]
>
> Armando
>
> Francesc Alted wrote:
> > A Wednesday 09 June 2010 10:00:50 V. Armando Solé escrigué:
> >
> >> Well, this seems to be quite close to what I need
> >>
> >> y = numpy.cumsum((x[1:]-x[:-1])/delta).astype(numpy.int)
> >> i1 = numpy.nonzero(y[1:] > y[:-1])
> >> y = numpy.take(x, i1)
> >>
> >
> > Perhaps this is a bit shorter:
> >
> > y = x[(x[1:] - x[:-1]) >= delta]
> >
> >
>
>
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