# [Numpy-discussion] avoiding loops when downsampling arrays

Sturla Molden sturla@molden...
Mon Feb 6 14:57:26 CST 2012

```Short answer: Create 16 view arrays, each with a stride of 4 in both dimensions. Test them against the conditions and combine the tests with an |= operator. Thus you replace the nested loop with one that has only 16 iterations. Or reshape to 3 dimensions, the last with length 4, and you can do the same with only four view arrays.

Sturla

Sendt fra min iPad

Den 6. feb. 2012 kl. 20:16 skrev "Moroney, Catherine M (388D)" <Catherine.M.Moroney@jpl.nasa.gov>:

> Hello,
>
> I have to write a code to downsample an array in a specific way, and I am hoping that
> somebody can tell me how to do this without the nested do-loops.  Here is the problem
> statement:  Segment a (MXN) array into 4x4 squares and set a flag if any of the pixels
> in that 4x4 square meet a certain condition.
>
> Here is the code that I want to rewrite avoiding loops:
>
> shape_out = (data_in.shape[0]/4, data_in.shape[1]/4)
> found = numpy.zeros(shape_out).astype(numpy.bool)
>
> for i in xrange(0, shape_out[0]):
>    for j in xrange(0, shape_out[1]):
>
>        excerpt = data_in[i*4:(i+1)*4, j*4:(j+1)*4]
>        mask = numpy.where( (excerpt >= t1) & (excerpt <= t2), True, False)
>        if (numpy.any(mask)):
>            found[i,j] = True
>
> Thank you for any hints and education!
>
> Catherine
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```

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