[Numpy-discussion] Counting the Colors of RGB-Image
Sun Jan 15 11:40:44 CST 2012
im_flat = im0[...,0]*65536 + im[...,1]*256 +im[...,2]
colours = np.unique(im_flat)
From: firstname.lastname@example.org [email@example.com] On Behalf Of Tony Yu [firstname.lastname@example.org]
Sent: 15 January 2012 18:03
To: Discussion of Numerical Python
Subject: Re: [Numpy-discussion] Counting the Colors of RGB-Image
On Sun, Jan 15, 2012 at 10:45 AM, <email@example.com<mailto:firstname.lastname@example.org>> wrote:
Counting the Colors of RGB-Image,
nameit im0 with im0.shape = 2500,3500,3
with this code:
tab0 = zeros( (256,256,256) , dtype=int)
tt = im0.view()
tt.shape = -1,3
for r,g,b in tt:
tab0[r,g,b] += 1
Is there a faster way in numpy to get this result?
Assuming that your image is made up of integer values (which I guess they'd have to be if you're indexing into `tab0`), then you could write:
>>> rgb_unique = set(tuple(rgb) for rgb in tt)
I'm not sure if it's any faster than your loop, but I would assume it is.
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