[Numpy-discussion] Assignment function with a signature similar to take?
Eric Moore
ewm@redtetrahedron....
Sat Nov 17 08:25:48 CST 2012
Is there a function that operates like 'take' but does assignment?
Specifically that takes indices and an axis? As far as I can tell no
such function exists. Is there any particular reason?
One can fake such a thing by doing (code untested):
s = len(a.shape)*[np.s_[:]]
s[axis] = np.s_[1::2]
a[s] = b.take(np.arange(1,b.shape[axis],2), axis)
Or by using np.rollaxis:
a = np.rollaxis(a, axis, len(a.shape))
a[..., 1::2] = b[..., 1::2]
a = np.rollaxis(a, len(a.shape)-1, axis)
But I don't really think that either of these are particularly clear,
but probably prefer the rollaxis solution.
Also, while I'm here, what about having take also be able to use a slice
object in lieu of a collection of indices?
-Eric
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