[Numpy-discussion] using numpy.argmax to index into another array
Sebastian Berg
sebastian@sipsolutions....
Wed Oct 31 19:30:53 CDT 2012
Hey,
On Wed, 2012-10-31 at 20:22 -0400, David Warde-Farley wrote:
> On Wed, Oct 31, 2012 at 7:23 PM, Moroney, Catherine M (388D)
> <Catherine.M.Moroney@jpl.nasa.gov> wrote:
> > Hello Everybody,
> >
> > I have the following problem that I would be interested in finding an easy/elegant solution to.
> > I've got it working, but my solution is exceedingly clunky and I'm sure that there must be a
> > better way.
> >
> > Here is the (boiled-down) problem:
> >
> > I have 2 different 3-d array, shaped (4,4,4), "a" and "b"
> >
> > I can find the max values and location of those max values in "a" in the 0-th dimension
> > using max and argmax resulting in a 4x4 matrix. So far, very easy.
> >
> > I then want to find the values in "b" that correspond to the maximum values in a.
> > This is where I got stuck.
> >
> > Below find the sample code I used (pretty clumsy stuff ...)
> > Can somebody show a better (less clumsy) way of finding bmax
> > in the code excerpt below?
>
Its a bit off-label usage (as the documentation says), so maybe its
slower for larger arrays, but as long as you choose along axis 0, you
could also use:
np.choose(amax, b)
> Hi Catherine,
>
> It's not a huge improvement, but one simple thing is that you can
> generate those index arrays easily and avoid the pesky reshaping at
> the end like so:
>
> In [27]: idx2, idx3 = numpy.mgrid[0:4, 0:4]
>
> In [28]: b[amax, idx2, idx3]
> Out[28]:
> array([[12, 1, 13, 3],
> [ 8, 11, 9, 10],
> [11, 11, 1, 10],
> [ 5, 7, 9, 5]])
>
> In [29]: b[amax, idx2, idx3] == bmax
> Out[29]:
> array([[ True, True, True, True],
> [ True, True, True, True],
> [ True, True, True, True],
> [ True, True, True, True]], dtype=bool)
>
> numpy.ogrid would work here too, and will use a bit less memory. mgrid
> and ogrid are special objects from the numpy.lib.index_tricks module
> that generate, respectively, a "mesh grid" and an "open mesh grid"
> (where the unchanging dimensions are of length 1) when indexed like
> so. In the latter case, broadcasting takes effect when you index with
> them.
>
> Cheers,
>
> David
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