[SciPy-dev] ticket 464

Alan G Isaac aisaac@american....
Thu Jul 26 13:39:21 CDT 2007

> Alan G Isaac wrote:
>>  That won't work.  A flattened matrix is still a matrix.
>>  But you can work with the flatiter representation.
>>      if max(x.shape) == 1: x = x.flat.next()

On Thu, 26 Jul 2007 20:30:58 +0300 dmitrey <openopt@ukr.net> apparently wrote:
> the matrix is converted to array before the check:
> So I had checked - it works

OK, I see.
But I still like the the above solution:
it's more general and in the context less confusing.
Or so I claim.  ;-)

Anyway, pick what you like.

Alan Isaac

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