Wed Aug 5 14:38:19 CDT 2009
--- On Wed, 8/5/09, Robert Kern <email@example.com> wrote:
> > I guess I don't really understand this too well - is
> the below correct behavior, and if so, why?
> >>>> b = np.broadcast(x, y, x, y)
> >>>> b.nd # doesn't return what I'd expect
> > 2
Why isn't that 4?
> Why don't you expect this? It's the correct answer.
> (x*y*x*y).shape == (3,3).
> >>>> del b # maybe problem is that I have to
> "clear" b first?
> >>>> # or maybe it's that all args have to be
> > ...
> >>>> b = np.broadcast(x, y, x * y)
> >>>> b.nd
> > 2
Why isn't that 3?
If x0, ..., xN are the arguments to `broadcast` and D = max(x0.nd, ..., xN.nd), is broadcast.nd necessarily <= D? If so, then I think I'm on the road to understanding.
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