[SciPy-user] Array manipulation
joris@ster.kuleuven....
joris@ster.kuleuven....
Wed Feb 14 02:34:40 CST 2007
Hi Nils,
It's not a one-liner, but it may serve you:
In [40]: n = 4
In [41]: i = 2
In [42]:
In [42]: A = arange(n*n).reshape(n,n)
In [43]: A
Out[43]:
array([[ 0, 1, 2, 3],
[ 4, 5, 6, 7],
[ 8, 9, 10, 11],
[12, 13, 14, 15]])
In [44]: I = range(n)
In [45]: I.remove(i)
In [46]: B = A[ix_(I,I)]
In [47]: B
Out[47]:
array([[ 0, 1, 3],
[ 4, 5, 7],
[12, 13, 15]])
Cheers,
Joris
On Wednesday 14 February 2007 09:02, Nils Wagner wrote:
>Hi,
>
>I would like to remove the i-th column and row from a two-dimensional
>array A. The remaining array
>should be kept and stored in B
>
>A = random.rand(n,n)
>
>This task is very easy if i is the first or last row/column. In that
>case one can use
>
>B = A[1:,1:]
>
>or
>
>B=A[:-1,:-1]
>
>But, what is the best way to get B if 0 < i < n-1 ?
>
>Nils
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