[SciPy-user] numpy array in ctype struct

Andrew Straw strawman@astraw....
Mon Jan 21 02:10:41 CST 2008

Hi Rob,

I am far from being a weave expert, having used it once in my life, but 
I think you may find some macros of interest if you examine the output C 
file. Examining these files was how I derived the following function:

def increment_fast(final_array_shape,  idxa,idxb,idxc):
    counts = numpy.zeros(final_array_shape, dtype=numpy.uint64)
    assert len(idxa.shape)==1
    assert len(idxa)==len(idxb)
    assert len(idxa)==len(idxc)

    code = r"""
    for (int i=0; i<Nidxa[0]; i++) {
        COUNTS3( IDXA1(i), IDXB1(i), IDXC1(i) )++;
    weave.inline( code, ['counts', 'idxa','idxb','idxc'])
    return counts

Note that "COUNTS3" is automatically defined from the 'counts' array and 
allows indexing more-or-less as if it's a rank-3 ndarray.

Rob Hetland wrote:
> On Jan 20, 2008, at 10:01 AM, Matthieu Brucher wrote:
>> This function signature suppose that you will access an element by  
>> data[i][j] which is not the way Numpy works.
> This seems to be the way the example attached by Paul Kienzle works,  
> albeit for fixed size arrays.  Would there be a way to dynamically  
> set the size for the fixed array, based on other input integers?
>>  You can create a wrapper function that will allocate a double** 1D  
>> array pointing to the adequate *double (start of a line), pass it  
>> to your function and then deallocate the array when returning from  
>> the function.
> Can you show an example?  I tried to do something similar, but failed  
> (due to poor coding skills..).  Also, is it better to create the  
> needed list of pointers on the python side, or the C side?
> I've had this sort of problem a few times, and I can't seem to find a  
> general solution anywhere.  Any advice would help,
> -Rob
> ----
> Rob Hetland, Associate Professor
> Dept. of Oceanography, Texas A&M University
> http://pong.tamu.edu/~rob
> phone: 979-458-0096, fax: 979-845-6331
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