[SciPy-user] comparing two lists/arrays

Scott Sinclair scott.sinclair.za@gmail....
Wed Jul 15 07:43:26 CDT 2009

> 2009/7/15 Robert Cimrman <cimrman3@ntc.zcu.cz>:
> nicky van foreest wrote:
>> Given two vectors x and y, the (perhaps) common mathematical
>> definition of x < y is that x_i < y_i for all i.  Thus, the
>> mathematical comparison x <y returns just one boolean, not an array of
>> booleans for each x_i < y_i.  I implemented this behavior as
>> prod(less(X,Y)) (I use less to be able to deal with lists X and Y
>> also). Is there perhaps a more straighforward/elegant/readible way to
>> achieve the same behavior?
> assuming x, y are numpy arrays: (x < y).all()

You could do the following to handle the case where they aren't:

>>> import numpy as np
>>> x = range(10)
>>> y = range(1, 11)
>>> np.all(x < y)


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