# [SciPy-User] moving window (2D) correlation coefficient

Zachary Pincus zachary.pincus@yale....
Wed Feb 10 10:42:19 CST 2010

```I bet that you could construct an array with shape (x,y,5,5), where
array[i,j,:,:] would give the 5x5 window around (i,j), as some sort of
mind-bending view on an array of shape (x,y), using a positive offset
and some dimensions having negative strides. Then you could compute
the correlation coefficient between the two arrays directly. Maybe?

Probably cython would be more maintainable...

Zach

On Feb 10, 2010, at 10:45 AM, Vincent Schut wrote:

> Hi,
>
> I need to calculate the correlation coefficient of a (simultaneously)
> moving window over 2 images, such that the resulting pixel x,y (center
> of the window) is the corrcoef((a 5x5 window around x,y for image
> A), (a
> 5x5 window around x,y for image B)).
> Currently, I just loop over y, x, and then call corrcoef for each x,y
> window. Would there be a better way, other than converting the loop to
> cython?
>
>
> For clarity (or not), the relevant part from my code:
>
>
> for y in range(d500shape[2]):
>     for x in range(d500shape[3]):
>         if valid500[d,y,x]:
>             window = spectral500Bordered[d,:,y:y+5, x:x
> +5].reshape(7, -1)
>             for b in range(5):
>                 nonzeroMask = (window[0] > 0)
>                 b01corr[0,b,y,x] =
>                 b01corr[1,b,y,x] =
>
>
> forget the 'if valid500' and 'nonzeroMask', those are to prevent
> calculating pixels that don't need to be calculated, and to feed only
> valid pixels from the window into corrcoef
> spectral500Bordered is essentially a [d dates, 7 images, ysize, xsize]
> array. I work per date (d), then calculate the corrcoef for images[0]
> versus images[2:], and for images[1] versus images[2:]
>
> Thanks,
> Vincent.
>
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```