[SciPy-User] [ANN] pyfftw-0.2 released

Sebastian Haase seb.haase@gmail....
Mon Feb 15 05:09:32 CST 2010

On Mon, Feb 15, 2010 at 12:06 PM, Sebastian Haase <seb.haase@gmail.com> wrote:
> On Mon, Feb 15, 2010 at 11:46 AM, David Cournapeau
> <david@silveregg.co.jp> wrote:
>> Sebastian Haase wrote:
>>> Has this changed from FFTW2 to FFTW3 ?
>>> It would really limit the use of plans, and make overall FFTs much
>>> slower. In my specific case I very often have 512x512 single-precision
>>> real arrays (images), that I would do ffts over and over again. But
>>> the pointers would change ....
>> You can, but you need to use the advanced plan API, or use the recently
>> added new-array execute function:
>> http://www.fftw.org/fftw3_doc/New_002darray-Execute-Functions.html#New_002darray-Execute-Functions
> so it sounds like the alignment is the "killer" argument for the whole idea:
> quote:
> """
> In general, only arrays allocated with fftw_malloc are guaranteed to
> be equally aligned (see SIMD alignment and fftw_malloc).
> The alignment issue is especially critical, because if you don't use
> fftw_malloc then you may have little control over the alignment of
> arrays in memory. For example, neither the C++ new function nor the
> Fortran allocate statement provide strong enough guarantees about data
> alignment. If you don't use fftw_malloc, therefore, you probably have
> to use FFTW_UNALIGNED (which disables most SIMD support). If possible,
> it is probably better for you to simply create multiple plans
> (creating a new plan is quick once one exists for a given size), or
> better yet re-use the same array for your transforms.
> """
> I guess this is really all new with version 3 of FFTW. I hope that
> "reating a new plan is quick once one exists for a given size" means
> "neglectable" for 512x512 arrays !?
> -S.
Oh, and it also seems to imply that FFTW3 is internally doing some
sort of plan-caching ... how else could it be faster the second time
David, do you have experience regarding this topic - or anyone else here ?

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