[SciPy-User] a=b operation in numpy
Tue Jul 2 10:24:59 CDT 2013
Does anybody know what is the rational in defining for the 'a=b' operation
a pointer copy and not a complete copy?
It is inconsistent from an algebraic point of view, since 'a=b' is not the
same as 'a=b+0'.
And it is also confusing for starters.
-------------- next part --------------
An HTML attachment was scrubbed...
More information about the SciPy-User